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Revista de la Unión Matemática Argentina
versión impresa ISSN 0041-6932versión On-line ISSN 1669-9637
Rev. Unión Mat. Argent. v.48 n.3 Bahía Blanca 2007
On pointed Hopf algebras associated with alternating and dihedral groups
Nicolás Andruskiewitsch and Fernando Fantino
Abstract. We classify finite-dimensional complex pointed Hopf algebras with group of group-like elements isomorphic to . We show that any pointed Hopf algebra with infinitesimal braiding associated with the conjugacy class of is infinite-dimensional if the order of is odd except for in . We also study pointed Hopf algebras over the dihedral groups.
2000 Mathematics Subject Classification. 16W30; 17B37
This work was partially supported by Agencia Córdoba Ciencia, ANPCyT-Foncyt, CONICET and Secyt (UNC)
Dedicado a María Inés Platzeck en sus # años
In this article, we continue the work of [AZ, AF] on the classification of finite-dimensional complex pointed Hopf algebras with non-abelian. We follow the Lifting Method - see [AS2] for a general reference; in particular, we focus on the problem of determining when the dimension of the Nichols algebra associated with conjugacy classes of is infinite. The paper is organized as follows. In Section 1, we review some general facts on Nichols algebras corresponding to finite groups. We discuss the notion of absolutely real element of a finite group in subsection 1.2. We then provide generalizations of [AZ, Lemma 1.3], a basic tool in [AZ, AF], see Lemmata 1.8 and 1.9. Section 2 is devoted to pointed Hopf algebras with coradical . We prove that any finite-dimensional complex pointed Hopf algebra with is isomorphic to the group algebra of ; see Theorem 2.6. This is the first finite non-abelian group such that all pointed Hopf algebras with are known. We also prove that , for any in of odd order, except for or in - see Theorem 2.3. This last case is particularly interesting. It corresponds to a "tetrahedron" rack with constant cocycle . The technique in the present paper does not provide information on the corresponding Nichols algebra. We also give partial results on pointed Hopf algebras with groups and , and on Nichols algebras , with even. In Section 3, we apply the technique to conjugacy classes in dihedral groups. It turns out that it is possible to decide when the associated Nichols algebra is finite-dimensional in all cases except for (if is odd), or or or or (if is even). See below for undefined notations. We finally observe in Section 4 that there is no finite-dimensional Hopf algebra with coradical isomorphic to the Hopf algebra discovered in [Ni], except for itself.
For we denote by the centralizer of in . If is a subgroup of and we will denote the conjugacy class of in . Sometimes we will write in rack notations , , . Also, if is a braided vector space, that is is a solution of the braid equation, then denotes its Nichols algebra.
We denote by the group of -th roots of 1 in .
1.1. Preliminaries. Let be a finite group, a conjugacy class of , fixed, an irreducible representation of , the corresponding irreducible Yetter-Drinfeld module. Let , …, be a numeration of and let such that for all . Then . Let , , . If and , then the coaction and the action of are given by
where , for some and . The Yetter-Drinfeld module is a braided vector space with braiding given by
| (1) |
for any , , where for unique , and . Since , the Schur Lemma says that
| (2) |
Let be a finite non-abelian group. Let be a conjugacy class of and let be an irreducible representation of the centralizer of a fixed . Let be the irreducible Yetter-Drinfeld module corresponding to and let be its Nichols algebra. As explained in [AZ, AF, Gñ], we look for a braided subspace of of diagonal type such that the dimension of the Nichols algebra is infinite. This implies that the dimension of is infinite too.
Lemma 1.1. If is a subspace of such that and , then .□
Recall that a braided vector space is of diagonal type if there exists a basis of and non-zero scalars , , such that , for all . A braided vector space is of Cartan type if it is of diagonal type and there exists , such that for all ; by we mean if is not a root of 1, otherwise it means the order of in the multiplicative group of the units in . Set for all . Then is a generalized Cartan matrix.
Theorem 1.2. ([H, Th. 4], see also [AS1, Th. 1.1]). Let be a braided vector space of Cartan type. Then if and only if the Cartan matrix is of finite type. □
We say that is real if it is conjugate to ; if is real, then the conjugacy class of is also said to be real. We say that is real if any is real.
The next application of Theorem 1.2 was given in [AZ]. Let be a finite group, , the conjugacy class of , irreducible; was defined in (2).
Lemma 1.3. Assume that is real. If then and has even order.□
If , this is [AZ, Lemma 2.2]; if then but is excluded by Lemma 1.1.
The class of real groups includes finite Coxeter groups. Indeed, all the characters of a finite Coxeter group are real valued, see subsection 1.2 below, and [BG] for . Therefore, we have:
Theorem 1.4. Let be a finite Coxeter group. If has odd order, then , for any . □
1.2. Absolutely real groups. Let be a finite group. We say that is absolutely real if there exists an involution in such that . If this happens, any element in the conjugacy class of is absolutely real and we will say that the conjugacy class of is absolutely real. We say that is absolutely real if any is so. The finite Coxeter groups are absolutely real. Indeed,
- the dihedral groups are absolutely real, by straightforward computations.
- the Weyl groups of semisimple finite dimensional Lie algebras are absolutely real, by [C, Th. C (iii), p. 45].
- is absolutely real, by Proposition 1.7 below.
- is absolutely real, we have checked it using GAP3, [S].
Remark 1.5. Let , be finite groups. We note:
- is absolutely real iff both and are absolutely real.
- is absolutely real iff both and are absolutely real.
- Assume abelian. Then is absolutely real iff has exponent 2, i. e. for some integer .
- If is absolutely real and is abelian of exponent 2 then is absolutely real.
We first discuss when an element of is absolutely real. Assume that is of type . Then iff is even.
Lemma 1.6. (a). If , then is absolutely real in .
(b). If is even then is absolutely real in .
Proof. Let for some and take
To prove (b), observe that there exists an involution such that , which is a product of "translations" of the 's. Since the sign of is , iff is even; (b) follows. We prove (a). By assumption there are at least two points fixed by , say , . By the preceding there exists an involution such that . If we are done, otherwise take ; is an involution and . □
Proposition 1.7. The groups and are absolutely real.
Proof. The type of is either , , or ; in the first two cases is absolutely real by Lemma 1.6 part (a), in the last two by part (b). Since (see [Hu, Section 2.13]), then the Coxeter group is absolutely real by Remark 1.5. □
1.3. Generalizations of Lemma 1.3. The next two Lemmata are variations of [AZ, Lemma 2.2]. A result in the same spirit appears in [FGV]. We deal with elements having a power in , the conjugacy class of . Clearly, if is in , then is in , for every . So, ; this implies that divides . Hence
with , recall (2).
Lemma 1.8. Let be a finite group, , the conjugacy class of and . Assume that there exists an integer such that , and are distinct elements and is in . If , then has even order and .
Proof. We assume that , thus . It is easy to see that
for every , . We will call , , , , ; so , for , , . The other relations between 's and 's are obtained from (4). For and or , we define . Hence, is a braided vector subspace of of Cartan type with
(i) Let us suppose that . This implies that . Since divides , we have that divides . We consider now two possibilities.
- Assume that . Then . Since divides , we have that divides . So, ; hence the result follows.
- Assume that . Then . We can see that divides . This implies that divides , a contradiction.
(ii) Let us suppose that . This implies that . Since divides , we have that divides . We consider now two possibilities.
- Assume that . Then . So, divides . It is easy to see that divides . Since and are relatively prime, must be , a contradiction.
- Assume that . This means that the subspace of is of Cartan type with
This concludes the proof. □
Lemma 1.9. Let be a finite group, , the conjugacy class of and such that . Assume that there exists an integer such that and is in .
- If , then has even order and .
- If , then either has even order and , or .
Proof. We will proceed and use the notation as in the proof of Lemma 1.8. If , then the result follows by Lemma 1.8. Assume that . This implies that divides , so divides .
(a) Let and in linearly independent and let - span of , with and . Thus is a braided vector subspace of of Cartan type with
(b) For we define , with and . Hence, is a braided vector subspace of of Cartan type with
(i) Assume that . This implies that . Since divides , we have that divides . Thus, divides ; hence , and the result follows.
(ii) Assume that . This implies that . Since divides , we have that divides . Hence, divides . If is a prime divisor of , then divides or , because divides . If divides , then divides , a contradiction. So, divides . Hence, divides , i.e. and the result follows. □
We recall that we will denote or the conjugacy class of an element in , and in , a representative of an isomorphism class of irreducible representations of . We want to determine pairs , for which , following the strategy given in [AZ, AF]; see also [Gñ].
The following is a helpful criterion to decide when a conjugacy class of an even permutation in splits in .
Proposition 2.1. [JL, Proposition 12.17] Let , with .
- If commutes with some odd permutation in , then and .
- If does not commute with any odd permutation in , then splits into two conjugacy classes in of equal size, with representatives and , and .□
Remarks 2.2. (i) Notice that if satisfies (1) of Proposition 2.1, then is real. The reciprocal is not true, e.g. consider in .
(ii) One can see that if in is of type , then satisfies (2) of Proposition 2.1 if and only if or , and , for all . Thus, if has even order, then is real.
We state the main Theorem of the section.
Theorem 2.3. Let and . Assume that is neither nor in . If , then has even order and .
Proof. If is even the result follows by Lemma 1.3 and Remark 2.2 (ii). Let us suppose that and odd . If is in , then the result follows by Lemma 1.3. Assume that . We consider two cases.
(i) If , then is in , and because . Hence, the result follows from Lemma 1.8.
(ii) Assume that . We know that there exist and in , necessarily odd permutations, such that and . Then and ; so is in . This implies that is in , and because is odd. Now, the result follows from Lemma 1.8.
Finally, let us suppose that , with type . If or , then is real, by Lemma 1.6 (a) and Remark 2.2, respectively. Hence, the result follows by Lemma 1.3. This concludes the proof. □
2.1. Case . Obviously, ; thus is not real. This case was considered in [AS1, Theorem 1.3].
2.2. Case . It is straightforward to check that is not real, since is not real in . Let in ; then the type of may be , or . If the type of is , then , for any in , by Lemma 1.1. If the type of is , then is not real; moreover we have
The following result is a variation of [AZ, Theorem 2.7].
Proposition 2.4. Let in of type . Then , for every in .
Proof. We can assume that . If we call , and , then and . If , and , then , , and
Let in and , where is the vector space affording . Thus is a braided vector space with braiding given by - see (1)- and , and
Clearly, , by Lemma 1.1. If we consider (resp. ), then is of Cartan type with matrix of coefficients given by
2.3. Case . Here is the key step in the consideration of this case.
Lemma 2.5. Let . Then , for every in .
Proof. Let . If the type of is either , or , we have that , by Lemma 1.3 and Proposition 1.7. Let us assume that the type of is . For , let and be as in the proof of Proposition 2.4. By Proposition 2.1 and straightforward computations, we have that and . Notice that , . Let and , where is the vector space affording ; then is a braided vector subspace of . Therefore, , by the same argument as in the proof of Proposition 2.4. □
As an immediate consequence of Lemma 2.5 we have the following result.
Theorem 2.6. Any finite-dimensional complex pointed Hopf algebra with is necessarily isomorphic to the group algebra of .
Proof. Let be a complex pointed Hopf algebra with . Let be the infinitesimal braiding of -see [AS2]. Assume that ; thus . Let be an irreducible submodule. Then , by Lemma 2.5. Hence, and . □
2.4. Case . Let be in . If the type of is , , , or , then is absolutely real by Lemma 1.6, and if the type of is , then is real because it has even order - see Remark 2.2 (ii). Hence, is a real group. We summarize our results in the following statement.
Theorem 2.7. Let be an irreducible Yetter-Drinfeld module over , corresponding to a pair . If , then , with , and .
Remark 2.8. In this Theorem we do not claim that the condition is sufficient.
Proof. Let be in . If the type of is
Let us suppose that the type of is ; we can assume that . It is easy to check that
Notice that . It is known that , where , , , and , are the following characters
and is the -dimensional representation given by
It is clear that , , , and . Then , by Lemma 1.1. Let us consider now that . We define , , , , and . It is clear that
If we have that and . We define . Then is a braiding subspace of of Cartan type with
Since is not of finite type we have that , by Theorem 1.2.
Finally, let us assume that the type of is . Then has elements and . We call , where , , , , . It is clear that if , with , or , then . This implies that , by Lemma 1.3. □
Remark 2.9. We can see that every maximal abelian subrack of has two elements. Hence, is a negative braided space in the sense of [AF].
2.5. Case , . Let , with even. We now investigate the Nichols algebras associated with by reduction to the analogous study for the orbit of in , [AF]. By Remark 2.2 (ii), and . So, we can determinate the irreducible representations of from those of . We know that if the type of is , then with , .
Some generalities and notation. Let be a finite group, a subgroup of of index two, and a representation of . It is easy to see that
Let such that ; thus . Let in . Then we have two cases:
- . If , then , and .
- . We have that and .
Moreover, if is an irreducible representation of , then is a restriction of some or is a direct summand of as in (ii), see [FH, Ch. 5].
Remark 2.10. If and , it is easy to check that
as braided vector spaces.
We apply these observations to the case and . We use some notations given in [AF, Section II.D].
Lemma 2.11. Assume that the type of is , with and even. Let in , with .
- If , then .
- If and , then
- if , then .
- Assume that . If , then . Assume that . If , with even or odd, or if , with even and or , where or , then the braiding is negative; otherwise, .
Proof. (a) follows by Remark 2.2 (ii) and Lemma 1.3. (b). Since , , with , and . Notice that because . Now, as the racks are the same, i.e. , we can apply [AF, Theorem 1]. □
Remark 2.12. Keep the notation of the Lemma. If is not isomorphic to its conjugate representation , then there exists such that and . Clearly, and act by scalar , and we have that as braided vector spaces. We do not get new information with the techniques available today.
We fix the notation: the dihedral group of order is generated by and with defining relations and . Let be a primitive -th root of 1 and let be the character of , . If then we denote the conjugacy class by or simply .
Theorem 3.1. Let be the irreducible Yetter-Drinfeld module over corresponding to a pair . Assume that its Nichols algebra is finite-dimensional.
- If is odd, then , where , .
- If is even, then is one of the following:
- where satisfies .
- where , and .
- or , where , , .
- or , where , , .
In the cases (i) and (ii) the dimension is finite. In the cases (iii) and (iv), the braiding is negative in the sense of [AF].
Remark 3.2. There are isomorphisms of braided vector spaces
Remark 3.3. Assume for simplicity that is odd and that , where , are integers . Then the (indecomposable) rack is a disjoint union of racks isomorphic to ; in other words, is an extension of by (and vice versa), see [AG, Section 2]. Thus, there is an epimorphism of braided vector spaces , as well as an inclusion . The techniques available today do not allow to compute the Nichols algebra from the knowledge of the Nichols algebra .
Remark 3.4. In Theorem 3.1 we do not claim that the conditions are sufficient. See Tables 1, 2. For instance, it is known that when - see [MS]; for other odd , this is open.
Table 1. Nichols algebras of irreducible Yetter-Drinfeld modules over , odd.
Let us now proceed with the proof of Theorem 3.1.
Proof. If , then and , from Lemma 1.1.
We consider now two cases.
CASE 1: odd.
(I) If , with , it is easy to see that and . Then , where , with a primitive -th root of . Let us consider ; it is a braided vector space of diagonal type. If , then , from Lemma 1.3. Assume ; so we have This is a contradiction because is odd.
(II) If , then and . Clearly, . On the other hand, is a negative braided vector space, since every abelian subrack of has one element; indeed , , if and only if .
Therefore, the part (a) of the Theorem is proved.
Table 2. Nichols algebras of irreducible Yetter-Drinfeld modules over , even.
CASE 2: even. Let us say .
(I) If , then and . Clearly, , for every with . On the other hand, if is such that , then it is straightforward to prove that , the exterior algebra of ; hence .
(II) If , ; then and . From Lemma 1.3, it is clear that , for every such that , i.e. . On the other hand, it is easy to see that , hence , for every with .
(III) If , then and . From Lemma 1.1, .
For the cases or , we note the following fact.
- If is odd and , we have that
- If is even and , we have that
The cases (i) and (ii) say that every maximal abelian subrack of has one and two elements, respectively. Hence, in both cases the braiding is negative. Indeed, the result is obvious for the case (i), while in the case (ii) we have that if and commute in , then and ; thus the braiding is negative.
(IV) If , then and . The result follows as in (III) using the isomorphism , , . □
4. On Nichols algebras over semisimple Hopf algebras
Let be a Hopf algebra. Let be a twist and let be the corresponding twisted Hopf algebra. If is a Hopf subalgebra of a Hopf algebra , then is a twist for and is a Hopf subalgebra of . Now, if is semisimple, then this induces a bijection
(7) |
that preserves standard invariants like dimension, Gelfand-Kirillov dimension, etc. Let now and let be the non-trivial twist defined in [Ni]. By (7), we conclude immediately from Theorem 2.6.
Theorem 4.1. Let be a finite-dimensional Hopf algebra with coradical isomorphic to . Then . □
Again, this is the first classification result we are aware of, for finite-dimensional Hopf algebras with coradical isomorphic to a fixed non-trivial semisimple Hopf algebra. Recently, a semisimple Hopf algebra was discovered in [GN]. This Hopf algebra is simple, that is it has no non-trivial normal Hopf subalgebra. Since there are finite-dimensional non-semisimple pointed Hopf algebras with group , there is a finite-dimensional non-semisimple Hopf algebra with coradical isomorphic to .
Acknowledgement. We are grateful to Professor John Stembridge for information on Coxeter groups, in particular reference [BG]. We thank Matías Graña, Sebastián Freyre and Leandro Vendramín for interesting discussions.
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Nicolás Andruskiewitsch
Facultad de Matemática, Astronomía y Física,
Universidad Nacional de Córdoba. CIEM - CONICET.
Medina Allende s/n
(5000) Ciudad Universitaria, Córdoba, Argentina
andrus@mate.uncor.edu
Fernando Fantino
Facultad de Matemática, Astronomía y Física,
Universidad Nacional de Córdoba. CIEM - CONICET.
Medina Allende s/n
(5000) Ciudad Universitaria, Córdoba, Argentina
fantino@mate.uncor.edu
Recibido: 16 de febrero de 2007
Aceptado: 2 de agosto de 2007